R S Aggarwal Quantitative Aptitude Chapter Wise PDF Free Download-Chapter 3rd Decimal Fractions

R S Aggarwal Quantitative Aptitude Chapter Wise PDF Free Download-Chapter 3rd Decimal Fractions

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Chapter 3rd Decimal Fractions

DECIMAL FRACTIONS Chapter 3rd 

IMPORTANT FACTS AND FORMULAE

 

  1. Decimal Fractions : Fractions in which denominators are powers of 10 are known as decimal fractions.  

                   Thus ,1/10=1 tenth=.1;1/100=1 hundredth =.01;

99/100=99 hundreths=.99;7/1000=7 thousandths=.007,etc

  1. Conversion of a Decimal Into Vulgar Fraction : Put 1 in the denominator under the decimal point and annex with it as many zeros as is the number of digits after the decimal point. Now, remove the decimal point and reduce the fraction to its lowest terms.

 

Thus, 0.25=25/100=1/4;2.008=2008/1000=251/125.

 

III.  1.  Annexing zeros to the extreme right of a decimal fraction does not change its value
Thus, 0.8 = 0.80 = 0.800, etc.

 

  1. If numerator and denominator of a fraction contain the same number of decimal
    places, then we remove the decimal sign.

Thus,   1.84/2.99 = 184/299 = 8/13;    0.365/0.584 = 365/584=5

 

  1. Operations on Decimal Fractions :

 

  1. Addition and Subtraction of Decimal Fractions : The given numbers are so
    placed under each other that the decimal points lie in one column. The numbers
    so arranged can now be added or subtracted in the usual way.

 

  1. Multiplication of a Decimal Fraction By a Power of 10 : Shift the decimal
    point to the right by as many places as is the power of 10.

Thus, 5.9632 x 100 = 596,32; 0.073 x 10000 = 0.0730 x 10000 = 730.

 

3.Multiplication of Decimal Fractions : Multiply the given numbers considering
them without the decimal point. Now, in the product, the decimal point is marked
off to obtain as many places of decimal as is the sum of the number of decimal
places in the given numbers.

Suppose we have to find the product (.2 x .02 x .002). Now, 2x2x2 = 8. Sum of decimal places = (1 + 2 + 3) = 6. .2 x .02 x .002 = .000008.

 

4.Dividing a Decimal Fraction By a Counting Number : Divide the given
number without considering the decimal point, by the given counting number.
Now, in the quotient, put the decimal point to give as many places of decimal as
there are in the dividend.

Suppose we have to find the quotient (0.0204 + 17). Now, 204 ^ 17 = 12. Dividend contains 4 places of decimal. So, 0.0204 + 17 = 0.0012.

 

 

  1. Dividing a Decimal Fraction By a Decimal Fraction : Multiply both the dividend and the divisor by a suitable power of 10 to make divisor a whole number. Now, proceed as above.

Thus, 0.00066/0.11 = (0.00066*100)/(0.11*100) = (0.066/11) = 0.006V

 

  1. Comparison of Fractions : Suppose some fractions are to be arranged in ascending or descending order of magnitude. Then, convert each one of the given fractions in the decimal form, and arrange them accordingly.

 

Suppose, we have to arrange the fractions  3/5, 6/7 and 7/9  in descending order.

 

now, 3/5=0.6,6/7 = 0.857,7/9 = 0.777….

 

since  0.857>0.777…>0.6, so 6/7>7/9>3/5

 

  1. Recurring Decimal : If in a decimal fraction, a figure or a set of figures is repeated continuously, then such a number is called a recurring decimal.

In a recurring decimal, if a single figure is repeated, then it is expressed by putting a dot on it. If a set of figures is repeated, it is expressed by putting a bar on the set

______

Thus 1/3 = 0.3333….= 0.3;  22 /7 = 3.142857142857…..= 3.142857

Pure Recurring Decimal: A decimal fraction in which all the figures after the decimal point are repeated, is called a pure recurring decimal.

 

Converting a Pure Recurring Decimal Into Vulgar Fraction : Write the repeated figures only once in the numerator and take as many nines in the denominator as is the number of repeating figures.

 

thus ,0.5 = 5/9;  0.53 = 53/59  ;0.067 = 67/999;etc…

 

 

Mixed Recurring Decimal: A decimal fraction in which some figures do not repeat and some of them are repeated, is called a mixed recurring decimal.

e.g., 0.17333 = 0.173.

 

Converting a Mixed Recurring Decimal Into Vulgar Fraction : In the numerator, take the difference between the number formed by all the digits after decimal point (taking repeated digits only once) and that formed by the digits which are not repeated, In the denominator, take the number formed by as many nines as there are repeating digits followed by as many zeros as is the number of non-repeating digits.

 

Thus 0.16 = (16-1) / 90 =  15/19 =  1/6;

____

0.2273 =  (2273 – 22)/9900 = 2251/9900

 

 

VII.  Some Basic Formulae :

 

  1. (a + b)(a- b) = (a2 – b2).
  2. (a + b)2 = (a2 + b2 + 2ab).
  3. (a – b)2 = (a2 + b2 2ab).
  4. (a + b+c)2 = a2 + b2 + c2+2(ab+bc+ca)
  5. (a3 + b3) = (a + b) (a2 – ab + b2)
  6. (a3 – b3) = (a – b) (a2 + ab + b2).
  7. (a3 + b3 + c3 – 3abc) = (a + b + c) (a2 + b2 + c2-ab-bc-ca)
  8. When a + b + c = 0, then a3 + b3+ c3 = 3abc

 

SOLVED EXAMPLES

 

Ex. 1. Convert the following into vulgar fraction:

            (i) 0.75             (ii) 3.004          (iii)  0.0056

 

Sol. (i). 0.75 = 75/100 = 3/4    (ii) 3.004 = 3004/1000 = 751/250    (iii) 0.0056 = 56/10000 = 7/1250

 

Ex. 2. Arrange the fractions 5/8, 7/12, 13/16, 16/29 and 3/4 in ascending order of magnitude.

 

Sol. Converting each of the given fractions into decimal form, we get :

5/8 = 0.624, 7/12 = 0.8125, 16/29 = 0.5517, and 3/4 = 0.75

Now, 0.5517<0.5833<0.625<0.75<0.8125

\ 16/29 < 7/12 < 5/8 < 3/4 < 13/16

 

Ex. 3. arrange the fractions 3/5, 4/7, 8/9, and 9/11 in their descending order.

 

Sol. Clearly, 3/5 = 0.6, 4/7 = 0.571, 8/9 = 0.88, 9/111 = 0.818.

Now, 0.88 > 0.818 > 0.6 > 0.571

\ 8/9 > 9/11 > 3/4 > 13/ 16

 

Ex. 4. Evaluate : (i) 6202.5 + 620.25 + 62.025 + 6.2025 + 0.62025

                             (ii) 5.064 + 3.98 + 0.7036 + 7.6 + 0.3 + 2

 

Sol.  (i)  6202.5                                                    (ii)  5.064

620.25                                                         3.98

62.025                                                       0.7036

6.2025                                                     7.6

+ __  0.62025                                                   0.3

6891.59775                                                 _2.0___

                                                                                  19.6476

 

Ex. 5. Evaluate : (i) 31.004 – 17.2368                       (ii) 13 – 5.1967

 

Sol.  (i)    31.0040                                                       (ii)   31.0000

17.2386                                                            – _5.1967

  • 8033

 

Ex. 6. What value will replace the question mark in the following equations ?

  • 49 + 378.352 + ? = 9318.678
  • ? – 7328.96 + 5169.38

 

Sol.  (i) Let       5172.49 + 378.352 + x = 9318.678

Then , x = 9318.678 – (5172.49 + 378.352) = 9318.678 – 5550.842 = 3767.836

(ii) Let      x – 7328.96 = 5169.38. Then, x = 5169.38 + 7328.96 = 12498.34.

 

Ex. 7. Find the products: (i) 6.3204 * 100               (ii) 0.069 * 10000

 

Sol.  (i) 6.3204 * 1000 = 632.04                     (ii) 0.069  * 10000 = 0.0690 * 10000 = 690

 

Ex. 8. Find the product:

            (i) 2.61 * 1.3                (ii) 2.1693 * 1.4           (iii) 0.4 * 0.04 * 0.004 * 40

 

Sol.  (i) 261 8 13 = 3393. Sum of decimal places of given numbers = (2+1) = 3.

2.61 * 1.3 = 3.393.

(ii) 21693 * 14 = 303702. Sum of decimal places = (4+1) = 5

2.1693 * 1.4 = 3.03702.

(iii) 4 * 4 * 4 * 40 = 2560. Sum of decimal places = (1 + 2+ 3) = 6

0.4 * 0.04 * 0.004 * 40 = 0.002560.

 

Ex. 9. Given that 268 * 74 = 19832, find the values of 2.68 * 0.74.

 

Sol.  Sum of decimal places = (2 + 2) = 4

2.68 * 0.74 = 1.9832.

 

Ex. 10. Find the quotient:

            (i) 0.63 / 9                    (ii) 0.0204 / 17                         (iii) 3.1603 / 13

 

Sol.  (i) 63 / 9 = 7. Dividend contains 2 places decimal.

0.63 / 9 = 0.7.

(ii) 204 / 17 = 12. Dividend contains 4 places of decimal.

0.2040 / 17  = 0.0012.

(iii) 31603 / 13 = 2431. Dividend contains 4 places of decimal.

3.1603 / 13 = 0.2431.

 

Ex. 11. Evaluate :

            (i) 35 + 0.07                            (ii) 2.5 + 0.0005

  • 09 + 43.9

 

Sol. (i) 35/0.07 = ( 35*100) / (0.07*100) = (3500 / 7) = 500

(ii) 25/0.0005 = (25*10000) / (0.0005*10000) = 25000 / 5 = 5000

(iii) 136.09/43.9 = (136.09*10) / (43.9*10) = 1360.9 / 439 = 3.1

 

Ex. 12. What value will come in place of question mark in the following equation?

            (i) 0.006 +? = 0.6                    (ii) ? + 0.025 = 80

 

Sol.  (i) Let 0.006 / x = 0.6, Then, x = (0.006 / 0.6) = (0.006*10) / (0.6*10) = 0.06/6 = 0.01

(ii) Let x / 0.025 = 80, Then, x = 80 * 0.025 = 2

 

Ex. 13. If (1 / 3.718) = 0.2689, Then find the value of (1 / 0.0003718).

 

Sol.  (1 / 0.0003718 ) = ( 10000 / 3.718 ) =  10000 * (1 / 3.718) = 10000 * 0.2689 = 2689.

 

                                                                                       ___                ______                  

Ex. 14. Express as vulgar fractions : (i) 0.37    (ii) 0.053     (iii)  3.142857

__                                                  ___

Sol. (i)  0.37 = 37 / 99 .                       (ii)  0.053 = 53 / 999

______             ______

(iii) 3.142857 = 3 + 0.142857 = 3 + (142857 / 999999) = 3 (142857/999999)

_                       __                      _

Ex. 15. Express as vulgar fractions : (i) 0.17           (ii) 0.1254        (iii)  2.536

_

Sol. (i) 0.17 = (17 – 1)/90 = 16 / 90 =  8/ 45

__

(ii) 0.1254 = (1254 – 12 )/ 9900 = 1242 / 9900 = 69 / 550

 

(iii)  2.536 = 2 + 0.536 = 2 + (536 – 53)/900 = 2 + (483/900) = 2 + (161/300) = 2 (161/300)

 

Ex. 16. Simplify:  0.05 * 0.05 * 0.05 + 0.04 * 0.04 * 0.04

0.05 * 0.05 – 0.05 * 0.04 + 0.04 * 0.04

 

Sol. Given expression  = (a3 + b3) / (a2 – ab + b2), where a = 0.05 , b = 0.04

                                     = (a +b ) = (0.05 +0.04 ) =0.09

 

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